It is proved that the equation "e ^ x-x ^ 2-3x-1 = 0" has and has only three roots

Let f (x) = e ^ x-x ^ 2-3x-1
f'(x)=e^x-2x-3
F "(x) = e ^ X-2 = 0, x = LN2 is the minimum of F '(x)
f'(ln2)=2-2ln2-3=-1-2ln2

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