There is only one root for the quick verification equation SiNx = X

There is only one root for the quick verification equation SiNx = X

It is proved that if f (x) = SiN x, then f '(x) = cos x 1 ≤ 0. F (x) decreases monotonically in (∞, + ∞). F (x) = sin X-1 = 0 has at most one root, while f (0) = 0, f (x) = 0 has and only one root, that is, the equation SiN x = x has only one root
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