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證明:令f(x)= sin x x,則f '(x)= cos x 1≤0 .' ' '∴f(x)在(∞,+∞)內單調减少.∴f(x)=sinx-1=0至多有一個根.而f(0)=0,∴f(x)= 0有且只有一個根.即方程sinx=x只有一個根. 看參考資料的最後一題
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