How much is the limit when x is close to zero

Let me tell you how to solve this problem. I can't type the formula. Ha ha. Let me tell you in words!
The idea is to rationalize the molecule. The denominator of the molecule is multiplied by X + 1 at the same time, the open root plus 1
In this way, the molecule becomes X. it can be reduced from the denominator X
The numerator becomes 1. The denominator becomes x + 1, the open root plus 1
Substituting x = 0, the limit of the result is half. 1 / 2

RELATED INFORMATIONS

1. Given the function f (x) = ax & # 178; - (2a & # 178; - 1) x-2a (a ∈ R), let the solution set of the inequality f (x) > 0 be a, and also know that B = {x | 1 ＜ x ＜ 3}, a ∩ B ≠ & # 216;, and find the value range of A
2. The known function f (x) = - 2A & # 178; X & # 178; + ax + 1 If f (x) = - 2A & # 178; X & # 178; + ax + 1 ≤ 0 is constant in the interval (1, + ∞), find the value range of real number a
3. Given the function f (x) = & # 188; X & # 8308; = & # 8531; ax & # 179; - A & # 178; X & # 178; + A & # 8308; (a > 0), find the monotone interval of the function
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5. If the function f (x) = ax & # 178; + BX + 3A + B defined on [a-1,2a] is even, then a + B =?
6. The function f (x) is even and is a decreasing function on (- ∞ 0). Try to compare the size of F (- 7 / 8) and f (2a & # 178; - A + 1)
7. Given that even function f (x) (x ≠ 0) is monotone on interval (0, + ∞), what is the sum of all x satisfying f (X & # 178; - 2x-1) = f (x + 1)?
8. If f (x) = (K-3) x & # 178; + (K-2) x + 3 is an even function, then the increasing interval of the function is________
9. Given that the function f (x) = (A-2) x & # 178; + (A-1) x + 3 is even, then the monotone increasing interval of F (x) is?
10. If the function f (x) is defined as an odd function on (- 1,1) and a decreasing function, if f (x-1) + F (1-x & # 178;) < 0, the value range of X is obtained
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