Given the function f (x) = ax & # 178; - (2a & # 178; - 1) x-2a (a ∈ R), let the solution set of the inequality f (x) > 0 be a, and also know that B = {x | 1 < x < 3}, a ∩ B ≠ & # 216;, and find the value range of A
ax²-(2a²-1)x-2a>0
(ax+1)(x-2a)>0
(1) When a = 0, the solution of F (x) > 0 is: x > 0;
(2) The solution of A0 is: 2A
RELATED INFORMATIONS
- 1. The known function f (x) = - 2A & # 178; X & # 178; + ax + 1 If f (x) = - 2A & # 178; X & # 178; + ax + 1 ≤ 0 is constant in the interval (1, + ∞), find the value range of real number a
- 2. Given the function f (x) = & # 188; X & # 8308; = & # 8531; ax & # 179; - A & # 178; X & # 178; + A & # 8308; (a > 0), find the monotone interval of the function
- 3. Given the function f (x) = x cube minus 4x & # 178; 1) find the monotone interval of function f (x) (2) find the function f (x) in the closed interval 0 The known function f (x) = x cube minus 4x & # 178; 1) Finding monotone interval of function f (x) (2) Finding the maximum and minimum of function f (x) in the closed interval 0 4
- 4. If the function f (x) = ax & # 178; + BX + 3A + B defined on [a-1,2a] is even, then a + B =?
- 5. The function f (x) is even and is a decreasing function on (- ∞ 0). Try to compare the size of F (- 7 / 8) and f (2a & # 178; - A + 1)
- 6. Given that even function f (x) (x ≠ 0) is monotone on interval (0, + ∞), what is the sum of all x satisfying f (X & # 178; - 2x-1) = f (x + 1)?
- 7. If f (x) = (K-3) x & # 178; + (K-2) x + 3 is an even function, then the increasing interval of the function is________
- 8. Given that the function f (x) = (A-2) x & # 178; + (A-1) x + 3 is even, then the monotone increasing interval of F (x) is?
- 9. If the function f (x) is defined as an odd function on (- 1,1) and a decreasing function, if f (x-1) + F (1-x & # 178;) < 0, the value range of X is obtained
- 10. The function y = f (x) is a decreasing function defined on R and an odd function. Solve the equation f (X & # 179; - x-1) + F (X & # 178; - 1) = 0
- 11. How much is the limit when x is close to zero
- 12. X divided by (1-radical x + 1) (x is greater than or equal to negative 1. X is not equal to 0)
- 13. The limit of F (x) is a, a > 0. It is proved that f (x) is equal to a under the triple root sign Can be added!
- 14. F (x) = [(x ^ 2 under the third radical) - (x under the second radical)] divide by X (x > = 0) to find the limit of F (x) at x = 0 F (x) = [(x ^ 2 under the third radical) - (x under the second radical)] divide by X (x > = 0) to find the limit of F (x) at x = 0
- 15. How to understand the instantaneous change rate of point derivative? When the increment of the independent variable approaches the limit of 0, that is, the instantaneous rate of change of the point derivative of the point, the problem is why the increment of the independent variable is still meaningful when it is all 0, and why there is still a rate of change when there is no change at the point?
- 16. Take a point (1,2) and a nearby point (1 + △ x, 2 + △ y) on the image of curve y = x2 + 1, then △ y △ x is______ .
- 17. Is derivative the instantaneous rate of change Just learning derivative, it's a bit abstract for me, I can't help but be grateful!
- 18. The problem of derivative in second grade mathematics Find the tangent equation of the curve y = SiNx at point a (6 / 6 π, 2 parts only 1)? 2. Find the tangent equation of the square of the parabola y = x parallel to the line 2x-y = 0? 3. Find the tangent equation of the point (0,0) and the square of the curve y = x? 4. Find the tangent equation of the point (1, - 1) on the curve y = XD 3 power - 2x? To write the process, thank you
- 19. It is known that f (x) is an odd function defined on R. when x ≥ 0, f (x) = x2-2x, then the expression of F (x) on R is () A. y=x(x-2)B. y=x(|x|-1)C. y=|x|(x-2)D. y=x(|x|-2)
- 20. It is known that the quadratic function f (x) = ax + BX (a, B are familiar, and a ≠ 0) satisfies the following conditions: F (- x + 5) = f (x-3), and the equation f (x) = x has equal roots (1) The expression of finding f (x) (2) whether there is a teacher's uncle m, n (m) or not