Given the function f (x) = ax & # 178; - (2a & # 178; - 1) x-2a (a ∈ R), let the solution set of the inequality f (x) > 0 be a, and also know that B = {x | 1 < x < 3}, a ∩ B ≠ & # 216;, and find the value range of A

Given the function f (x) = ax & # 178; - (2a & # 178; - 1) x-2a (a ∈ R), let the solution set of the inequality f (x) > 0 be a, and also know that B = {x | 1 < x < 3}, a ∩ B ≠ & # 216;, and find the value range of A

ax²-(2a²-1)x-2a>0
(ax+1)(x-2a)>0
(1) When a = 0, the solution of F (x) > 0 is: x > 0;
(2) The solution of A0 is: 2A