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F(x)=x^3-x-1を設定すると、F‘(x)=3*x^2-1,F‘(x)=6x 順序F‘(x)=0,得x=±(根号3)/3; x=(ルート3)/3の場合、F‘'((ルート3)/3)>0、F(x)の場合、最小=-2(ルート3)/9-1
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