If the equation x3-x-1 = 0 has a root on the interval (a, b) (a ∈ Z., B ∈ z) of length 1, then a + B =?

Let f (x) = x ^ 3-x-1, then f '(x) = 3 * x ^ 2-1, f' (x) = 6x
Let f '(x) = 0, then x = ± (radical 3) / 3;
When x = (radical 3) / 3, f '((radical 3) / 3) > 0, then f (x) has a minimum value = - 2 (radical 3) / 9 - 1

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