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設F(x)=x^3-x-1,則F‘(x)=3*x^2-1 ,F‘'(x)=6x 令F‘(x)=0,得x=±(根號3)/3 ; 當x=(根號3)/3時,F‘'((根號3)/3)>0,此時F(x)有極小值=-2(根號3)/9 -1
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