D (arctanx ^ 2 + e ^ 2x + LNX + radical 3) = let y = x / LNX find y "=
Y = x / LNX, then the first derivative y '= 1 / ln (x) - 1 / (LN (x) ^ 2, the second derivative y' '= - 1 / [XLN (x)] + 2 / [x (LN (x)) ^ 3]
RELATED INFORMATIONS
- 1. What is the corresponding function of the new image after the image translation vector a = (π / 4,0) of the function y = cos (2 / 3x + π / 6)
- 2. After the image translation vector (- π / 6 1 / 2) of the function y = cos 2x, the function y =? A 1/2+cos(2x- π/3) B 1/2+cos(2x+π/3) c cos(2x+π/3)-1/2 D cos(2x+π/6)+1/2
- 3. If the image of a positive scale function passes through a point (- 1,2), then the image must pass through a point () A. (1,2)B. (-1,-2)C. (2,-1)D. (1,-2)
- 4. Given that y 3 is in direct proportion to x, and x = 1, y = 5, translate the image of the function so that it passes (2, - 1), and find the analytic expression of the line after translation
- 5. Given that Y-3 is in positive proportion to X and x = 2, y = 7 shifts the function image so that it passes through the point (2, - 1) and finds the analytic expression of the translated line
- 6. The image of positive scale function y = - 2x is shifted one unit length to the left, and the analytic expression of the function is?
- 7. Find the linear function expression (drawing solution) after translating the image of function y = - 2x + 1 to the right by 2 unit lengths It doesn't have to be a drawing step
- 8. The image of a first-order function is shifted 2 units to the right to get a straight line y = - 2x, and through the point a (- 4,2), the expression of the function is obtained, and the area of the figure enclosed by the function image and the coordinate axis is obtained
- 9. The functional expression of the image obtained by translating the image of y = 1 / X one unit to the right is
- 10. The image of a positive scale function passes through a (- 2, 3), and the expression of the function is written
- 11. Given the function f (x) = LNX + X2 - (B + radical 2 / 2) x, 1, if the function y = f (x) is an increasing function on [radical 2, + ∞], find the value range of real number B
- 12. By translating the image of function y = lnx-2 into vector a = (negative 1,2), the image of function y = f (x) is obtained
- 13. After y = (2x-1) / (x + 1) is translated according to vector a = (1, - 2), the function analytic expression of the image is () A.y=3/x B.y=-3/x C.y=-2/x D.y=2/x
- 14. The image of the function f (x) = (2-x) / (x-1) is obtained by translating the image of the function f (x) = (1 + x) / X along the position vector a = (m, n), and finding m, n
- 15. After translating the image of function y = x ^ 2 according to vector a, the image of function y = x ^ 2 + 6x + 11 is obtained, then vector a is
- 16. Urgent Teaching: given the square of y = x + 6x + 11, translate its image vector (→ a), get the image of function y = x square, find the vector (→ a) There should be a detailed process
- 17. Parity of F (x) = loga (x + radical x ^ 2 + 1)
- 18. Let f (x) be a decreasing function on a set of real numbers. If a + B ≤ 0, then the following is true () A. f(a)+f(b)≤-[f(a)+f(b)]B. f(a)+f(b)≤f(-a)+f(-b)C. f(a)+f(b)≥f(-a)+f(-b)D. f(a)+f(b)≥-[f(a)+f(b)]
- 19. Let f (x) be a decreasing function on a set of real numbers. If a + B ≤ 0, then the following is true () A. f(a)+f(b)≤-[f(a)+f(b)]B. f(a)+f(b)≤f(-a)+f(-b)C. f(a)+f(b)≥f(-a)+f(-b)D. f(a)+f(b)≥-[f(a)+f(b)]
- 20. Given function f (x) = LNX - (B / x) (B is a real number) Find the extremum of function f (x) if B = - 1