The image of a first-order function is shifted 2 units to the right to get a straight line y = - 2x, and through the point a (- 4,2), the expression of the function is obtained, and the area of the figure enclosed by the function image and the coordinate axis is obtained

The image of a first-order function is shifted 2 units to the right to get a straight line y = - 2x, and through the point a (- 4,2), the expression of the function is obtained, and the area of the figure enclosed by the function image and the coordinate axis is obtained

∵ the image of a linear function is shifted 2 units to the right to get a straight line y = - 2x
Let y = - 2 (X-2) + B
And ∵ over point a (- 4,2)
∴2=-2(-4-2)+b
∴b=-10
∴y=-2(x-2)-10
=-2x-6
Let x = 0 and y = 0 respectively, the two intersections of the solution with X axis and Y axis are (0, - 6), (- 3,0) respectively
Area s = 1 / 2x6x3 = 9