Given f (x) = (x power of A-X power of a), G (x) = (x power of a + x power of a) Verification: [f (x)] 2 + [g (x)] 2 = g (2x)

Given f (x) = (x power of A-X power of a), G (x) = (x power of a + x power of a) Verification: [f (x)] 2 + [g (x)] 2 = g (2x)

[f(x)]2+g[(x)]2=[(a)x-(a)(-x)]2+[(a)x+(a)(-x)]2
=[(a)x]2-2*(a)x*(a)(-x)+[(a)(-x)]2+[(a)x]2+2*(a)x*(a)(-x)+[(a)(-x)]2
=2(a)(2x)+2(a)(-2x)=2[(a)(2x)+(a)(-2x)]=2g(2x)