Finding the minimum value of Y & # 178; + 4Y + 8 Read the process below Solution: Y & # 178; + 4Y + 8 = y & # 178; + 4Y + 4 + 4 = (y + 2) &# 178; + 4 ≥ 4 The minimum value of Y & # 178; + 4Y + 8 is four The minimum value of a & # 178; + A + 1 can be obtained by imitating it

a^2+a+1=(a+1/2)^2+3/4>=3/4
So the minimum value is: 3 / 4

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1. Read the following solution process, find the minimum value of Y square + 4Y + 8. Solution: y square + 4Y + 8 = y square + 4Y + 4 + 4 = (y + 2) square + 4 ≥ 4, so the minimum value of Y square + 4Y + 8 is 4. Follow the above solution process, find the minimum value of m square + m + 1 and the maximum value of 4 - (x square) + 2x ~ ~ ~ urgent, everyone help me
2. Read the following questions and their solutions: find the minimum value of Y & # 178; + 4Y + 8 Solution: Y & # 178; + 4Y + 8 = y & # 178; + 4Y + 4 + 4 = (y + 2) &# 178; + 4 ≥ 4, so the minimum value of Y & # 178; + 4Y + 8 is 4. Follow the above solution process to find the minimum value of M & # 178; + m + 1
3. Y & # 178; + 4Y + 8 = y & # 178; + 4Y + 4 + 4 = (y + 2) & # 178; + 4 ≥ 4, so the minimum value of Y & # 178; + 4Y + 8 is the minimum value of M & # 178; + m + 4
4. It is known that the root of the equation x + 9x + 4 = 0 is α β 1? 2. The quadratic equation with square root of α and square root of β is?
5. To solve the quadratic equation of one variable (1) x2 + 3x + 1 = 0 (2) x2-10x + 9 = 0 (3) (2x-1) 2 = (3x + 2) 2 (4) (x-1) (x + 2) = 2 (x + 2)
6. 4X square - 4Y square - 4x + 4Y + 11 = 2
7. Square of 9x + square of 4Y = 31 to find 4x
8. Calculate [the square of x plus 6x plus 9] × x plus the square of three thirds of x plus 9x plus 18
9. Square of (x + 6x) + 18 (x + 6x) + 81 How to factorize
10. Find all non negative integer solutions of X that make algebraic formula 1 + X / 2 greater than 2x-1 / 3 hold
11. x2-y2-6x+9
12. X2-6x + 9-y2~~
13. [compare the size of X2 (square of x) - 4x + 3 and X2 (square of x) - 6x + 9] Compare the size of x2-4x + 3 and x2-6x + 9
14. (x / x2-9) - (1 / x2 + 6x + 9) calculation
15. Find the maximum and minimum value of function f (x) in the interval [- π / 4, π / 4] f（x）=sin（2x+π/3）+sin（2x-π/3）+2cos²x-1，x∈R
16. If the function y = - x + 6x + 9 has a maximum value of 9 and a minimum value of - 7 in the interval [a, b] (a < B < 3), then a =?, B =?
17. The function y = - x ^ 2 + 6x + 9 is in the interval [A.B] (A
18. The function f (x) = - x ^ 2-6x + 9 in the interval a, B, (a)
19. Find the maximum and minimum value of the function y = x2 + 6x-7 in the interval [- 8,3]
20. The function y = - X & # 178; + 6x + 9 is in the interval [A.B] (A