It is known that the root of the equation x + 9x + 4 = 0 is α β 1? 2. The quadratic equation with square root of α and square root of β is?

It should be X & # 178; + 9x + 4 = 0. According to Weida's theorem, it is obtained that α + β = - 9 α β = 4 (1) 1 / α + 1 / β = (α + β) / α β = - 9 / 41 / α + 1 / β = 1 / α β = 1 / 4, so the univariate quadratic equation of 1 / α, 1 / β & nbsp; root is X & # 178; + 9 / 4 x + 1 / 4 = 0, that is 4x & # 178; + 9x + 1 = 0 (2) α & # 178; + β & # 1

RELATED INFORMATIONS

1. To solve the quadratic equation of one variable (1) x2 + 3x + 1 = 0 (2) x2-10x + 9 = 0 (3) (2x-1) 2 = (3x + 2) 2 (4) (x-1) (x + 2) = 2 (x + 2)
2. 4X square - 4Y square - 4x + 4Y + 11 = 2
3. Square of 9x + square of 4Y = 31 to find 4x
4. Calculate [the square of x plus 6x plus 9] × x plus the square of three thirds of x plus 9x plus 18
5. Square of (x + 6x) + 18 (x + 6x) + 81 How to factorize
6. Find all non negative integer solutions of X that make algebraic formula 1 + X / 2 greater than 2x-1 / 3 hold
7. It is known that the a + 3 power of - 4Y multiplied by the 3 power of X and the 3-B power of 4x multiplied by the 4 power of y can be combined into one term, and the algebraic formula 3 can be obtained
8. The values of the algebraic expressions 4x + 2 and 3x-9 are opposite to each other
9. On the system of equations 3x + YK + 1, x + 3Y = 3 of X, and X + y is nonnegative, what is the range of K?
10. If the solutions of the equations 2x + y = K + 1,3x-y = 3 about X, y are a pair of negative numbers, then the value range of K is?
11. Y & # 178; + 4Y + 8 = y & # 178; + 4Y + 4 + 4 = (y + 2) & # 178; + 4 ≥ 4, so the minimum value of Y & # 178; + 4Y + 8 is the minimum value of M & # 178; + m + 4
12. Read the following questions and their solutions: find the minimum value of Y & # 178; + 4Y + 8 Solution: Y & # 178; + 4Y + 8 = y & # 178; + 4Y + 4 + 4 = (y + 2) &# 178; + 4 ≥ 4, so the minimum value of Y & # 178; + 4Y + 8 is 4. Follow the above solution process to find the minimum value of M & # 178; + m + 1
13. Read the following solution process, find the minimum value of Y square + 4Y + 8. Solution: y square + 4Y + 8 = y square + 4Y + 4 + 4 = (y + 2) square + 4 ≥ 4, so the minimum value of Y square + 4Y + 8 is 4. Follow the above solution process, find the minimum value of m square + m + 1 and the maximum value of 4 - (x square) + 2x ~ ~ ~ urgent, everyone help me
14. Finding the minimum value of Y & # 178; + 4Y + 8 Read the process below Solution: Y & # 178; + 4Y + 8 = y & # 178; + 4Y + 4 + 4 = (y + 2) &# 178; + 4 ≥ 4 The minimum value of Y & # 178; + 4Y + 8 is four The minimum value of a & # 178; + A + 1 can be obtained by imitating it
15. x2-y2-6x+9
16. X2-6x + 9-y2~~
17. [compare the size of X2 (square of x) - 4x + 3 and X2 (square of x) - 6x + 9] Compare the size of x2-4x + 3 and x2-6x + 9
18. (x / x2-9) - (1 / x2 + 6x + 9) calculation
19. Find the maximum and minimum value of function f (x) in the interval [- π / 4, π / 4] f（x）=sin（2x+π/3）+sin（2x-π/3）+2cos²x-1，x∈R
20. If the function y = - x + 6x + 9 has a maximum value of 9 and a minimum value of - 7 in the interval [a, b] (a < B < 3), then a =?, B =?