If {x, XY, LG (XY)} = {0, | x |, y} then log8 (x ^ 2 + y ^ 2)
lg(xy)=0
xy=1
Then: | x | = 1
And y = x, | x | is not equal to y
So x = - 1, y = - 1
Original formula = log8 (2)
=1/3
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