In the mapping f: A-B, a = b = {(x, y) | x belongs to R, y belongs to R}, F: (x, y) → (x + 2Y, 2x-y), then the element in B corresponding to element (3,1) in a = is

In the mapping f: A-B, a = b = {(x, y) | x belongs to R, y belongs to R}, F: (x, y) → (x + 2Y, 2x-y), then the element in B corresponding to element (3,1) in a = is

From F: (x, y) → (x + 2Y, 2x-y), we can see that the element in B corresponding to (3,1) is (5,5)