If the solutions X and y of the system 3x = y + 32kx − (K − 1) y = 6 are opposite to each other, then K=______ ．

Given the equations, 3x = y + 3 ①2kx−(k−1)y＝6… ② By substituting y into equation 2, 2kx - (k-1) (3x-3) = 6, ｜ x = 9 − 3K3 − K, substituting x into equation 1, y = 18 − 6k3 − K, (K ≠ 3) ∵ x + y = 0, ｜ 9 − 3K3 − K + 18 − 6k3 − k = 0, the solution is k = 3

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