Let f (x) = ax ^ 2 + BX (a ≠ 0) satisfy the condition 1. F (- 1 + x) = f (- 1-x); there is only one common point between the image of 2 function f (x) and the line y = X

Let f (x) = ax ^ 2 + BX (a ≠ 0) satisfy the condition 1. F (- 1 + x) = f (- 1-x); there is only one common point between the image of 2 function f (x) and the line y = X

f(-1+x)=f(-1-x)
Then the axis of symmetry x = - 1
So - B / (2a) = - 1
b=2a
There is only one point in common with the line y = X
Then the equation AX ^ 2 + BX = x has two equal solutions
b=2a
So ax ^ 2 + (2a-1) x = 0
x[ax+(2a-1)]=0
x=0,x=-(2a-1)/a
There are two equal solutions
-(2a-1)/a=0
a=1/2,b=1
f(x)=x^2/2+x