How many 7 digits (decimal) in which the sum of each digit is even? It must be decimal~

Simple, 7 digits from 1000000 to 9999999
A total of 999999 - 1000000 + 1 = 9000000
There are as many odd and even digit sums
Therefore, there are 9000000 / 2 = 4500000 7 digits whose sum of digits is even

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