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As shown in the figure, if the digit a corresponding to point a on the number axis, the number corresponding to point B on the number axis is B, and a and B satisfy | a + 2 | plus (B-1) = 0 (1) Finding the length of line ab (2) Point C is the digit x corresponding to the number axis, and X is the solution of the equation 2x-1 = 1 / 2x plus 2. Is there a point P on the number axis, such that PA plus Pb = PC? If it exists, find out the number corresponding to P, but it does not exist. Please explain the reason (3) Under the conditions of (1) (2), point a, B and C begin to move on the number axis. If point a moves to the left at the speed of one unit length per second, and point B and point C move to the right at the speed of four unit lengths per second and nine unit lengths per second respectively, suppose that after T seconds, the distance between point B and point C is expressed as BC, and the distance between point a and point B is ab, Please explain the reason, if not, find out the value! I want it today!
（1）∵|a+2|+(b-1)=0
∴a=-2,b=1
∴AB=3
（2）2x-1=1/2×x+2
x=2
Point P exists, P = - 1
(3) AB distance = 3 + (4 + 1) t
BC distance = 1 + (9-4) t
AB-BC=3+（4+1）t-[1+（9-4）t]
=3+5t-1-5t
=2
The value of ab-bc does not change, value = 2
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