The distance between the line 4x-3y + 4 = 0 and the line 8x-6y + a = 0 is 2 Is self-learning high school curriculum for detailed explanation!

The distance between ax + by + C1 = 0 and ax + by + C2 = 0 is d = | C1-C2 | / √ (A & # 178; + B & # 178;)
The distance between 4x-3y + 4 = 0 and 8x-6y + a = 0
That is, the distance between the lines 8x-6y + 8 = 0 and 8x-6y + a = 0
d=|8-a|/√(8²+6²)=2
That is | 8-A | = 20
8-A = 20 or 8-A = - 20
A = - 12 or a = 28

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