If the sum of three times of a prime number and two times of another prime number is 100, what are the two prime numbers

Prime numbers are all odd except 2. The problem is that the sum of three times of a prime number and two times of another prime number is 100, which is even. Therefore, the first prime number must be even, that is, 2
So three times the first number is 2 × 3 = 6
So the second number is: (100-6) △ 2 = 47
So these two prime numbers are 2 and 47, respectively

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