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Given that C is a real number and the opposite number of a root of equation x2-3x + C = 0 is a root of equation x2 + 3x-c = 0, find the solution of equation x2 + 3x-c = 0 and the value of C
Let a root of equation x2-3x + C = 0 be a, then a root of equation x2 + 3x-c = 0 is - A; substitute the two into a2-3a + C = 0, a2-3a-c = 0; subtract the two equations to get C = 0; then equation x2 + 3x-c = 0 is equation x2 + 3x = 0, the solution is X1 = 0, X2 = - 3; the solution of equation x2 + 3x-c = 0 is X1 = 0, X2 = - 3; C = 0
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