In the period from 4 o'clock to 5 o'clock, when is the minute hand perpendicular to the hour hand? The linear equation 6x-0.. 5x = ()

Let the first time around 4:5 be 4:x, and the second time around 4:44 be 4:y. (30 / 60) * x + 120 - (360 / 60) x = 90x = 60 / 11 [30 - (30 / 60) * y] + 6y-180 = 90Y = 480 / 11 A: the first minute hand perpendicular to the hour hand is 4:60 / 11; the second minute hand perpendicular to the hour hand is 4:480 / 11

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