5x + 4Y + Z = 0, 3x + y-4z = 1, x + y + Z = - 2. If we use a system of linear equations with three variables, we have to have a process~

5x + 4Y + Z = 0, 3x + y-4z = 1, x + y + Z = - 2. If we use a system of linear equations with three variables, we have to have a process~

We may as well set it as ①, ②, ③ formula ① × 4 plus ② to eliminate Z. similarly, ① - ③ to eliminate Z, we can get binary linear equations, and then solve them

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