There are four real numbers. The first three numbers form an equal ratio sequence, and their product is - 8. The last three numbers form an equal difference sequence, and their product is - 80 | Math enthusiast | Mathematical art

There are four real numbers. The first three numbers form an equal ratio sequence, and their product is - 8. The last three numbers form an equal difference sequence, and their product is - 80

Let the four numbers be BQ, B, BQ, a, then B3 = - 82bq = a + bab2q = - 80, the solution is a = 10B = - 2q = - 2, or a = - 8b = - 2q = 52, so the four numbers are 1, - 2, 4, 10, or - 45, - 2, - 5, - 8

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