As shown in the figure, point AB is on the straight line Mn, ab = 11cm, and the radius of circle a and circle B is 1cm

Set the departure time as T seconds
Circumscribed case: distance between two centers = sum of two radii
In the case of inscribed: the distance between the centers of two elements = the radius of the big circle - the radius of the small circle
(1) Garden A is circumscribed on the left side of garden B, and 11-2t = 1 + T + 1 is solved by itself
(2) The original A is inscribed to the left of the center of the original B, 11-2t = 1 + T - 1
(3) The original A is inscribed on the right side of the center of the original B, 2T = 1 + T - 1 + 11
(4) The original A is circumscribed on the right side of the original B, 2T = 1 + T + 1 + 11
You can draw a picture to know the meaning of the equation. It's very nice

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