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As shown in the figure, P is the point on the fixed length line AB, and C and D respectively start from P and B and move to the left along the straight line AB at the speed of 1cm / s and 2cm / S (C is on the line AP and D is on the line BP) (2) under the condition of (1), q is the point on the straight line AB, and aq-bq = PQ, calculate the value of pqab. (3) under the condition of (1), if there is CD = 12ab after 5 seconds of C and D movement, then point C stops moving and point D stops moving Continue to move (point D is on line Pb), m and N are the midpoint of CD and PD respectively. The following conclusions can be drawn: (1) the value of pm-pn remains unchanged; (2) the value of mnab remains unchanged, which means that only one conclusion is correct. Please find out the correct conclusion and evaluate it (1) If there is always PD = 2Ac when C and d move to any time, please indicate the position of P on line ab
(1) According to the motion speed of C and D, we know: BD = 2pc ∵ PD = 2Ac, ∵ BD + PD = 2 (PC + AC), that is Pb = 2AP, ∵ point P is at 13 points on the line AB; (2) as shown in the figure: ∵ aq-bq = PQ, ∵ AQ = PQ + BQ; AQ = AP + PQ, ∵ AP = BQ, ∵ PQ = 13ab, ∵ pqab = 13. When point Q 'is on the extension line of AB, AQ' - AP = PQ 'so AQ' - BQ '= PQ = AB, so pqab = 1; (3) the value of mnab remains unchanged When point C stops, there are CD = 12ab, CM = 14ab, PM = cm − CP = 14ab − 5, PD = pb-bd = 23ab-10, PN = 12 (23ab − 10) = 13ab − 5, Mn = PN − PM = 112AB; when point C stops and point d continues to move, the value of Mn remains unchanged, so mnab = 112abab = 112
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- 1. As shown in the figure, point P is the point on the fixed length line AB, and points c and D respectively start from P and B and move to the left along the straight line AB at the speed of 1cm / s and 2cm / s As shown in the figure, P is the point on the fixed length line AB, and C and D respectively start from P and B and move to the left along the line AB at the speed of 1cm / s and 2cm / S (C is on the line AP and D is on the line BP) (1) If C and d move to any moment, there is always PD = 2Ac and ab = 6 Quick, quick,
- 2. As shown in the figure, P is the point on the fixed length line AB, and C and D respectively start from P and B and move to the left along the straight line AB at the speed of 1cm / s and 2cm / S (C is on the line AP) As shown in the figure, P is the point on the fixed length line AB, and C and D respectively start from P and B and move to the left along the line AB at the speed of 1cm / s and 2cm / S (C is on the line AP and D is on the line BP) (3) Under the condition of (1), if CD = 1 / 2Ab happens to exist after C and d move for 5 seconds, then point C stops moving and point d continues to move (point D is on line Pb), and m and N are the midpoint of CD and PD respectively. This paper attempts to explore the quantitative relationship between line Mn and AB, and gives a conclusion and reasons
- 3. As shown in the figure, P is the point on the fixed length line AB, and C and d start from P and B respectively along the straight line AB at the speed of 1cm / s and 2cm / s
- 4. As shown in the figure, P is the point on the fixed length line AB, C and d start from P and B respectively and move to the left along the straight line AB at the speed of 1cm / s and 2cm / s, C is on the line AP, (C is on the line AP, D is on the line BP) when C and d move to any time, there is always PD = 2Ac, then AP / AB equals () a.1/2 b.1/3 c.1/4 d.1/5. (2) under the condition of (1), q is a point on the line AB, and aq-bq = PQ, find the value of PQ / ab
- 5. As shown in the figure, P is the point on the fixed length line AB, and C and D respectively start from P and B and move to the left along the line AB at the speed of 1cm and 2cm per second. C is on the line AP D is on line BP (1) What is the quantitative relationship between the length of BD and PC? Explain the reason (2) If C and d move to any time, there will always be PD = 2Ac, please explain the position of point P on line AB! Figure: a -------- C --- P -------- D -------- B 20: 30, plus points!
- 6. It is known that: as shown in Figure 1, M is a certain point on the fixed length line AB, C and D respectively start from m and B and move to the left along the straight line BA at the speed of 1cm / s and 3cm / s, and the direction of motion is shown by the arrow (C is on the line am, D is on the line BM) (1) If AB = 10cm, when points c and d move for 2S, find the value of AC + MD. (2) if points c and d move, there is always MD = 3aC, fill in the blank directly: am=______ Ab. (3) under the condition of (2), where n is a point on the line AB and an-bn = Mn, the value of mnab is obtained
- 7. Points a and B are on the straight line Mn, ab = 11 cm, circle a moves from left to right at the speed of 2 cm per second, and at the same time, the radius of circle B increases, its radius is r cm, and the relationship between the radius and time t is r = 1 + T (T > 0) Wen: how many seconds after point a starts, the two elements are tangent The radius of circle a and B is 1 cm
- 8. As shown in the figure, point AB is on the straight line Mn, ab = 11cm, and the radius of circle a and circle B is 1cm
- 9. As shown in the figure, points a and B are on the straight line Mn, ab = 11cm, the radii of ⊙ A and ⊙ B are 1cm, and ⊙ a moves at a speed of 2cm per second As shown in the figure, points a and B are on the straight line Mn, ab = 11cm, and the radii of ⊙ A and ⊙ B are all 1cm. ⊙ a moves from left to right at the speed of 2cm per second. At the same time, the radius of ⊙ B is also increasing. The relationship between the radius R (CM) and time t (s) is r = 1 + T (t ≥ 0) (1) Try to write out the functional expression between the distance D (CM) between points a and B and the time t (s); (2) How many seconds after point a starts, the two circles are tangent?
- 10. As shown in the figure: points a and B are on the straight line Mn, ab = 11 cm, circle a, and the radius of circle B is 1 cm. Circle a moves from left to right at the speed of 2 cm per second. At the same time, the radius of circle B is also increasing. The relationship between radius R (CM) and time t (s) is r = 1 + T (t ≥ 0
- 11. As shown in the figure, point C is on line AB, and points m and N are the midpoint of AC and BC respectively. (1) if AC = 8cm and CB = 6cm, find the length of line Mn; (2) if C is a line As shown in the figure, point C is on line AB, and points m and N are the midpoint of AC and BC respectively (1) If AC = 8cm, CB = 6cm, find the length of line Mn; (2) Can you guess the length of Mn if C is any point of AB, AC + CB = A and other conditions remain unchanged;
- 12. As shown in Figure 5, point C is the point on line AB, point m is the midpoint of line AC, and point n is the midpoint of line BC. (2) AC: CB = 3:2, Mn = 10cm, Find the length of am A----M----C--N--B
- 13. As shown in the figure, the line AB = 10cm, the point C is any point on AB, the point m is the midpoint of AC, and the point n is the midpoint of CB
- 14. If M is the midpoint of AC, n is the midpoint of BC, and ab = 10cm, the length of Mn is obtained
- 15. Given that four points a, B, C and D are on the straight line L, ab = 10cm, CD = 4cm, and points m and N are the midpoint of AC and BD respectively, the length of segment Mn is calculated I'm in a hurry, By 20 o'clock today A total of 10 cases Please list them one by one DC = CD, so there are many cases I know the answer, To write a little paper, ..... And please use easy to understand language to answer,,,,,,
- 16. As shown in the figure, line AB = 8cm, C is the point on line AB, AC = 3.2cm, M is the midpoint of AB, n is the midpoint of AC. (1) find the length of line cm; (2) find the length of line Mn
- 17. As shown in the figure, line BD = 1 / 3AB = 1 / 4CD, points m and N are the midpoint of line AB and CD respectively, and Mn = 20cm |------|--|----|----|---------| A M D B N C
- 18. As shown in the figure, ab = CD, CB = 1 / 3AB, points m and N are the midpoint of AB and CD respectively, and Mn = 8cm Anyway, there are two answers. What should I do In silence
- 19. As shown in the figure, line BD equals one third AB equals one fourth CD, points m and N are the midpoint of line AB and CD respectively, and Mn equals 20 cm, so find the length of AC
- 20. As shown in the figure, take a point D on AB, take a point C on the extension line of AB, so that BD = 1 / 3AB = 1 / 4bc, and the midpoint of line AB and BC are m, n respectively, Mn = 7cm, Finding the length of line AB, CD