Given that AC: CD: DB = 4:5:6, M is the midpoint of AC, n is the midpoint of BD, Mn = 6cm, find the length of ab

MN=MC+CD+DN=AC/2+CD+DB/2=(4/15AB)/2+5/15AB+(6/15AB)/2=2/3AB
AB=3/2MN=3/2*6=9cm

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