Given that CD = 4 / 1ab, AC = BD, m and N are the midpoint of AC and DB respectively, and Mn = 10cm, find the length of ab

Let AB be xcm in length, then CD is 1 / 4x cm, AC + BD = 3 / 4x cm, and because m and N are the midpoint of AC and DB respectively, so MC + DN = 1 / 2 (AC + BD) = 3 / 8x cm, because Mn = 10cm, so Mn = CD

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