Given that the square root of (a + B-1) and the cubic of (a-2b + 3) are opposite to each other, try to find the square root of a times a plus B plus 8 / 9 Please hurry up--------

Given that the square root of (a + B-1) and the cubic of (a-2b + 3) are opposite to each other, try to find the square root of a times a plus B plus 8 / 9 Please hurry up--------

If the numbers are opposite to each other, the sum equals 0
So (a + B-1) & sup2; + (a-2b + 3) & sup2; = 0
If one is greater than 0, the other is less than 0
So both are equal to zero
So a + B-1 = 0
a-2b+3=0
The solution is b = 4 / 3, a = - 1 / 3
So a * a + B + 8 / 9 = 7 / 3
So the square root is plus or minus (root sign 21) / 3

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