Given that a, B and C are three unequal real numbers, and X / (a-b) = Y / (B-C) = Z / (C-A), find the value of X + y + Z

Let X / (a-b) = Y / (B-C) = Z / (C-A) = t
be
x + y + z
= (a-b)t + (b-c)t + (c-a)t
=(a-b+b-c+c-a)t
= 0

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