If a, B, C are all prime numbers, where a is the smallest, and a + B + C = 44, AB + 3 = C, then AB + C=______ ．

∵ a, B, C are all prime numbers, and a + B + C = 44, where a is the smallest, ∵ a = 2, according to the meaning of the problem, there are 2 + B + C = 442b + 3 = C, the solution is b = 13C = 29, ∵ ab + C = 2 × 13 + 29 = 55

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