If the 3-dimensional column vectors α and β satisfy α t β = 2, then the nonzero eigenvalue of the matrix β α t is? Although the characteristic polynomials and eigenvalues of AB and Ba are the same, why is the nonzero eigenvalue equal to 2? To Yin Yang double edged sword: β α t β = β (α t β) = 2 β or not

If the 3-dimensional column vectors α and β satisfy α t β = 2, then the nonzero eigenvalue of the matrix β α t is? Although the characteristic polynomials and eigenvalues of AB and Ba are the same, why is the nonzero eigenvalue equal to 2? To Yin Yang double edged sword: β α t β = β (α t β) = 2 β or not

According to the definition, β α t β = β (α t β) = 2 β