14 (a ^ 2 + B ^ 2 + C ^ 2) = (a + 2B + 3C) ^ 2, and a = 1, the value of B and C
14 (a ^ 2 + B ^ 2 + C ^ 2) = (a + 2B + 3C) ^ 2, and a = 1, the original formula is 13 + 10B ^ 2 + 5C ^ 2-4b-6c-12bc = 0,
(b-2) ^ 2 + (C-3) ^ 2 + (3b-2c) ^ 2 = 0, so B = 2, C = 3
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