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Tan α = 2, find the value of [(sin α + cos α) / (sin α + cos α)] + cos & # 178; α
Is it [(sin α + cos α) / (sin α - cos α)] + cos & # 178; α?
The denominator of [(sin α + cos α) / (sin α - cos α)] is divided by cos α
=(tanα+1)/(tanα-1)=3
Cos & # 178; α = cos & # 178; α / (Sin & # 178; α + cos & # 178; α) numerator denominator divided by cos & # 178; α
=1/(tan²α+1)=1/5
Original formula = 3 + 1 / 5 = 16 / 5
If it is [(sin α - cos α) / (sin α + cos α)] + cos & # 178; α?
The denominator of [(sin α - cos α) / (sin α + cos α)] is divided by cos α
=(tanα-1)/(tanα+1)=1/3
Cos & # 178; α = cos & # 178; α / (Sin & # 178; α + cos & # 178; α) numerator denominator divided by cos & # 178; α
=1/(tan²α+1)=1/5
Original formula = 1 / 3 + 1 / 5 = 8 / 15
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