Why does the value of root 6 have no negative number, only positive number, but the square root of 6 has negative number?

RELATED INFORMATIONS

• 1. Do negative numbers have square roots? Is an imaginary number the square root of a negative number I remember that negative numbers have no square root What is the imaginary number? If not, why not
• 2. Is the negative 2 square of a negative number a positive number, such as (- 2) ^ - 2
• 3. How to calculate the square of negative number
• 4. How to calculate the negative square of a constant
• 5. How to calculate the negative square of a number? No, it's a power. It's a negative number
• 6. Is the square of a negative number negative or positive without brackets?
• 7. It is known that: x2 + Y2 + 4x-6y + 13 = 0, where x and y are rational numbers, then YX=______ ．
• 8. Given that x ^ 2 + y ^ 2 + 4x-6y + 13 = 0, X and y are rational numbers, find the value of x ^ y
• 9. Write 5 rational numbers (which cannot be repeated), 3 of which are non negative; 3 of which are non positive; 5 of which are all positive
• 10. Arbitrarily write 5 rational numbers (without repetition), of which 3 are non positive and non negative, and 5 cannot be integers
• 11. Why do negative numbers have no square root?
• 12. Can't the root of the root be negative and zero?
• 13. Simple operation of the power of the product of grade seven 1) The fifth power of 2 × the fourth power of 5 2) (- two thirds) to the power of 2005 × 1.5 to the power of 2005 3) 8 to the power of 8 × (- 1 / 4) to the power of 12 4) The fifth power of (- 3) × (- 2 / 3) × the sixth power of (- 5) It's gone Don't give me a short answer - thank you first.
• 14. The power of 3-trace product (simple operation + process) (1)2^5*5^4 (2)8^8*(-1/4)^12 (3)(-3)^5*(-2/3)^5*(-5)^6 For these three questions, it is necessary to simplify the calculation and complete the process! 2^5x5^4 8^8x(-1/4)^12 (-3)^5x(-2/3)^5x(-5)^6
• 15. Simple calculation of product's power 1.8^3×（1/4)^4 2.(-1/8)^3×2^9
• 16. Part eight: the calculation of product's power, 1.[(x-y^3]^4*[-(y-x)^2]^5*(x-y) 2.(-2x^2y)^3-8(x^2)^2*(-x)^2*(-y)^3 The second question is wrong 2.(-2x^2*y)^3-8(x^2)^2*(-x)^2*(-y)^3 One more question 3.(a^m+b^n-2)* (-2a^m-2b^n-2)^2* (3a^m+3b^n-2)^3* (1/2b^n-2+1/2a^m)^4
• 17. On the calculation of product's power ② （-a^3*b^6）^4+（-a^4*b^8）^3 ③ -（-x^2）^3*（-x^2）^2-x*（-x^3）^3 ④（-2a^2）^3 + （-3a^3）^2 +（-a）^6
• 18. A problem about the power of product is going to be solved tonight (0.5 times 3 and 2 / 3) 2009 times (- 2 times 3 / 11) 2008
• 19. Several problems about the power of product 1. The third power of ab 2. The fourth power of (- AB) 3. (x to the power of 3, y to the power of 2m) 4. The 5th power of (2m power of x) - the 2m power of 5 (5m power of x) 5. The second power of (- 3x) and the third power of [(- 2x)]
• 20. The formula of product's power calculation What is the sum of the sixth power of (- 2XY quadratic) and the third power of (- 3x quadratic y quartic)