Given that x ^ 2 + y ^ 2 + 4x-6y + 13 = 0, X and y are rational numbers, find the value of x ^ y

x^2+y^2+4x-6y+13=0
x^2+4x+4+y^2-6y+9=0
（x+2）²+（y-3）²=0
x=-2,y=3
x^y=-8

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