If the rational numbers x and y satisfy the quadratic power of | x + Y-3 | + (X-Y + 1) = 0, find the quadratic power of (x multiplied by the quadratic power of Y) multiplied by the quadratic power of (x multiplied by the quadratic power of Y) Value of
|x+y-3|+(x-y+1)^2=0
|x+y-3|=0,(x-y+1)^2=0
x+y-3=0
x-y+1=0
Solution
x=1
y=2
(xy^2)^2*(x^2y^2)^2
=x^2y^4*x^4y^4
=x^6y^8
=1^6*2^8
=1*256
=256