Given that a is the sum of the opposite number of - 6 and the absolute value of - 10, B is the number of integers whose absolute value is not greater than 3, and C is the smallest natural number, the value of a + 2b-c is obtained? To be specific, it's better to have an absolute value

Given that a is the sum of the opposite number of - 6 and the absolute value of - 10, B is the number of integers whose absolute value is not greater than 3, and C is the smallest natural number, the value of a + 2b-c is obtained? To be specific, it's better to have an absolute value

A = - (- 6) + | - 10 | = 16; if there are 7 integers with absolute value no more than 3, then B = 7; C = 0, so a + 2b-c = 16 + 14-0 = 30