Let a = {x | x2 < 4}, B = {x | (x-1) (x + 3) < 0} (1) find the set a ∩ B; (2) if the solution set of inequality 2x2 + ax + B < 0 is B, find the value of a and B

Let a = {x | x2 < 4}, B = {x | (x-1) (x + 3) < 0} (1) find the set a ∩ B; (2) if the solution set of inequality 2x2 + ax + B < 0 is B, find the value of a and B

(1) A = {x | - 2 < x < 2}, B = {x | - 3 < x < 1}. From the graph, we know that a ∩ B = {x | - 2 < x < 1}, that is, a ∩ B = (- 2,1), (2) ∩ inequality 2x2 + ax + B < 0 has the solution set of B = {x | - 3 < x < 1}, and {3 + ax + B = 0, then − 3 + 1 = − A2 − 3 × 1 = B2, and the solution is a = 4, B = - 6