If / M + 1 / + (n-2) 2 = 0, then the root of the original equation (m2-3m-4) X2 - (N2 + 4) X-1 = 0 is /M + 1 / / is the absolute value sign
∵|m+1|≥0,(n-2)^2≥0
∴m+1=0,n-2=0
∴m=1,n=2
∴(1-3-4)x^2-(4+4)x-1=0
-6x^2-8x-1=0
∴x1=(-4-√10)/3,x2=(-4+√10)/3
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