7 to the power of 24 - 1 can be divided by two numbers between 30 and 40

7 to the power of 24 - 1 can be divided by two numbers between 30 and 40

=(7-1) (7 + 1) (7 ^ 2 + 1) (7 ^ 4 + 1) (7 ^ 16 + 7 ^ 8 + 1) is obviously not a multiple of 7
＝6*8*50*A
＝32*3*25*A
Obviously, 3|a
Obviously: 30 32 36 40 satisfied check: odd: 31 33 37 39 even: 34 38
7 ^ 24 power:
Divide by 11 remainder: (10,24) = 27 ^ 2 = 49! = 1
Divided by 13, the remainder (12,24) = 12, the remainder = 1
Divide by 31 remainder: (30, 24) = 6, 7 ^ 6 = 18 ^ 3 = 18 * 14 = 10! = 1
Divide by 37 remainder: (36,24) = 12 7 ^ 12 = 12 ^ 6 = - 4 ^ 3! = 1
Divide by 17 remainder: (16,24) = 8 7 ^ 8 = (- 2) ^ 4 = 16! = 1
Divided by 19: (18,24) = 6 7 ^ 6 = 11 ^ 3 = 11 * 7 = 1
So the original number is also a multiple of 13 and 19
The following numbers: 30 32 36 38 39 40 meet the requirements