When Xiao Ming solved the equation 2x − 15 + 1 = x + A2, due to carelessness, when the denominator is removed, the left 1 of the equation is not multiplied by 10, so the solution obtained is x = 4. Try to find the value of a, and correctly find the solution of the equation

When Xiao Ming solved the equation 2x − 15 + 1 = x + A2, due to carelessness, when the denominator is removed, the left 1 of the equation is not multiplied by 10, so the solution obtained is x = 4. Try to find the value of a, and correctly find the solution of the equation

∵ when the denominator is removed, only 1 on the left side of the equation is not multiplied by 10, 2 (2x-1) + 1 = 5 (x + a), substituting x = 4 into the above formula, the solution is a = - 1. The original equation can be reduced to: 2x − 15 + 1 = x − 12, the denominator is removed, 2 (2x-1) + 10 = 5 (x-1) is removed, the bracket is removed, 4x-2 + 10 = 5x-5 is obtained, the term is shifted and the similar term is merged, the - x = - 13 coefficient is changed to 1, x = 13, so a = - 1, x = 13