If the sum of two integers a and B can be divided by 6, then a and B can be divided by 3

Inverse proposition: if two integers a and B can be divisible by 3, then the sum of a and B can be divisible by 6
Original proposition: false a = 1, B = 5
Inverse proposition: false a = 6, B = 9

RELATED INFORMATIONS

1. In a mathematical problem, a positive integer whose sum of all numbers is a multiple of 3 can be divided by 3 and its inverse proposition, no proposition, in the inverse proposition, the number of false propositions is the number of true propositions?
2. Write a positive integer whose sum of all the numbers in the proposition is a multiple of 3, an inverse proposition, a no proposition, an inverse no proposition that can be divided by 3, and judge whether it is true or false
3. Six digit 2006 can be divided by 99, and its last two digits are_____________ Process + answer
4. Six digit 2003 can be divided by 99, and its last two digits are______ ．
5. Six digit 2003 can be divided by 99, and its last two digits are______ ．
6. If the six digit 1992 can be divided by 105, then the last two digits are______ ．
7. If six digit 2003 () () can be divided by 45, what are its last two digits? If four digit 36ab can be divided by 2,3,4,5,9 at the same time, what is 36ab? Add 10 points to answer the second question
8. Take any one from 1,2,3,... To 9, record and put it back, take n times continuously, and find the probability that the product of the number taken can be divided by 10?
9. From 1 to 9, there are nine numbers that are put back. Take three times, one at a time. The product of three numbers can be divided by 10
10. The probability that the product of the three integers can be divisible by 10 is obtained by randomly taking three times from nine integers from one to nine, one at a time I read the answers on the Internet, but I can't understand them, especially the ones with one five and two five. I don't know how to calculate the probability I thought there must be a 5 that is 1 / 9, there must be an even number 4 / 9, another random 9 / 9, but the multiplication is not right 214, why not? It's best to write the reason step Otherwise I can't understand it
11. Take two numbers from 2, 4, 5, 6, 7, 8, 9 and 10 at a time to make their sum divisible by 3. How many methods are there?
12. If you add 1 to a number, it will be divisible by 6; if you add 3 to it, it will be divisible by 8; if you add 5 to it, it will be divisible by 10 We also know that this number is divided into 6, 8 and 10, and the sum of the quotients is 235. What is the maximum of this number?
13. From 1 to 10, 1,7 can't be divided by 2,3,5, and several numbers from 1 to 1000 can't be divided by 2,3,5
14. The greatest common factor of two numbers divisible by 2 and 5 must be divisible by 10. Right or wrong
15. Characteristics of numbers divisible by 8, 125, 7, 11, 13 The number that can be divided by 8, 125, 11, 13 is more detailed!
16. Characteristics of numbers divisible by 11 13 7 8 4
17. Characteristics of numbers divisible by 7.11.13.9
18. Can you explain the characteristics that can be divided by 7, 11, 13 Thank you very much~ OK, I'll add! For example, let's be more detailed! I'll be home!
19. What are the characteristics of numbers divisible by 7? What are the characteristics of numbers divisible by 13?
20. What are the characteristics of numbers divisible by 7, 11 or 13?