If the six digit 1992 can be divided by 105, then the last two digits are______ ．

Because 105 = 3 × 5 × 7, 105 can be divisible by 3, 5 and 7 at the same time. According to the characteristics of the number divisible by 5, we know that there are seven possibilities for this six digit number: 199200199230199260199290199215199245199275. Finally, we use 7 to try to know that 199290 can be divisible by 7. Therefore, 199290 can be divisible by 105, and its last two digits are 90

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