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因為105=3×5×7,所以105能同時被3、5和7整除.根據能被5整除的數的特徵,可知這個六位數有如下七個可能:199200199230199260199290199215199245199275.最後用7去試除知,199290能被7整除.所以,199290能被105整除,它的最後兩位數是90.故答案為:90.
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