Take any one of the 100 integers from 1 to 100, and try to find the probability that the number can be divided by 6 or 8

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• 1. Take any one of 100 integers and calculate the probability that this number can not be divided by 6 or 8
• 2. Write the numbers 1, 2, 3, 4 and 5 on the five cards, mix them and arrange them in a row. What is the probability that the number can be divided by 2 or 5? Why is the last place divisible by 2 only 2 or 4? There are 48 kinds of 2 * 4 The last place divisible by 5 can only be 5, total = 24 kinds How did you get here?
• 3. 5_ 383_ 8_ 2_ 936_ 5_ 8_ 203_ 9_ 3_ The reason why the probability of dividing 396 by any number 0 ~ 9 added at the line is 1
• 4. The probability that any number from 1 to 100 can be divided by 5 or 7
• 5. Take any number from 1-1000 integers to calculate the probability that the data can be divided by 2 or 5
• 6. What is the probability that any one of the two digits can be divided by 2 or 3
• 7. In all two digits, take any number and find the probability that the number can be divided by 2 or 3
• 8. In all two digits, take any number and find the probability that the number can be divided by 2 or 3
• 9. Four of the five numbers 0, 1, 3, 5 and 7 can form many four digit numbers that can be divided by 11. What is the smallest four digit number?
• 10. Take 6 numbers from the 10 numbers 0-9 to form a maximum 6-digit number divisible by 11
• 11. Take any number from 1 to 100 and find the probability that the number can be divided by 2 or 3
• 12. Take any three of the 10 numbers from 0 to 9 to form a three digit number without repetition. The probability that this number cannot be divided by 3 is______ ．
• 13. The probability of being divisible by 2 or 3 in 10-99,
• 14. Take a number randomly from the integers of 1 &; 2000. What's the probability that the number can't be divided by 6 or 8?
• 15. Take a random number from the integers of 1-2000. What's the probability that the integers can't be divided by 6 or 8 Because 333 is less than 2000 / 6 and less than 334, P (a) = 333 / 2000! Why should p (a) be expressed in this way and 333 / 2000?
• 16. Probability theory question: randomly select integers from 1 to 2000. What's the probability that the integers can't be divided by 6 or 8? The answer is 1917 / 2000
• 17. In the 1 to 2000 random integer, ask the probability that the integer can not be divided by 6 or 8
• 18. The probability that the product of the three integers can be divisible by 10 is obtained by randomly taking three times from nine integers from one to nine, one at a time I read the answers on the Internet, but I can't understand them, especially the ones with one five and two five. I don't know how to calculate the probability I thought there must be a 5 that is 1 / 9, there must be an even number 4 / 9, another random 9 / 9, but the multiplication is not right 214, why not? It's best to write the reason step Otherwise I can't understand it
• 19. From 1 to 9, there are nine numbers that are put back. Take three times, one at a time. The product of three numbers can be divided by 10
• 20. Take any one from 1,2,3,... To 9, record and put it back, take n times continuously, and find the probability that the product of the number taken can be divided by 10?