(n-2) &; 180 = 5 × 360, how to calculate this

RELATED INFORMATIONS

• 1. How to solve that 3 / y minus 2 / x equals 360?
• 2. Five consecutive integers, let the smallest number be X. write the sum of these five numbers; when these five numbers are what numbers, their sum is equal to 300
• 3. The sum of five consecutive integers is 300. What's the largest one?
• 4. For five consecutive integers, the sum of squares of the first three numbers equals the sum of squares of the last two numbers
• 5. There are five consecutive integers. The sum of the squares of the first three integers is equal to the sum of the squares of the last two integers According to the conditions, the equation is listed and reduced to a general formula
• 6. If an integer greater than one is removed from 300205243 to leave 15, then this number is equal to ()
• 7. The sum of several continuous natural numbers is 1994, the smallest of which is () The sum of several continuous natural numbers is 1994, and the smallest one is ()
• 8. The sum of all the digits of the natural number n is 1994, so when the value of n is the smallest, it is () digits and ()
• 9. 1/（1*4）+1/（4*7）+1/（7*10）+1/（10*13）．．．．．．+1/（2002*2005）+1/（2005*2008）
• 10. Who knows 1 / (1 * 4) - 1 / (4 * 7) - 1 / (7 * 10) - 1 / (10 * 13)... - 1 / (2002 * 2005) - 1 / (2005 * 2008)
• 11. Why n * 180 degrees - (n-2) × 180 degrees = 360 degrees Help me
• 12. How to prove that the sum of exterior angles of n-polygon is 360 degree
• 13. Who can prove that the sum of exterior angles of n-shape is 360 degrees pai314
• 14. s=nπr²/360° What's the formula?
• 15. How about (n-2) × 180? = 3 × 360
• 16. 360/n+180*(n-2)=2005
• 17. A quarter of a ton is a fraction of 360 kg
• 18. 1 / 2 + 1 / 6 + 1 / 12 +... 1 / N (n + 1) = 2005 / 2006, how much is n (please answer in detail, including solution ideas)
• 19. 1 / 2 + 1 / 6 + 1 / 12 +. = n times N + 1 = 2006 / 2005, n = how much
• 20. If 2 / 1 + 6 / 1 + 12 / 1 ········ n + (n + 1) / 1 equals 2006 / 2005, then n equals?