There are five consecutive integers. The sum of the squares of the first three integers is equal to the sum of the squares of the last two integers According to the conditions, the equation is listed and reduced to a general formula

x^2+(x+1)^2+(x+2)^2=(x+3)^2+(x+4)^2
x^2-8x-20=0
x=10
10,11,12,13,14

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